b^2x^2-9bx+8=0

Solution for b^2x^2-9bx+8=0 equation:

Simplifying
b2x2 + -9bx + 8 = 0

Reorder the terms:
8 + -9bx + b2x2 = 0

Solving
8 + -9bx + b2x2 = 0

Solving for variable 'b'.

Factor a trinomial.
(1 + -1bx)(8 + -1bx) = 0

Subproblem 1
Set the factor '(1 + -1bx)' equal to zero and attempt to solve:

Simplifying
1 + -1bx = 0

Solving
1 + -1bx = 0

Move all terms containing b to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1bx = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1bx = 0 + -1
-1bx = 0 + -1

Combine like terms: 0 + -1 = -1
-1bx = -1

Divide each side by '-1x'.
b = x-1

Simplifying
b = x-1
Subproblem 2
Set the factor '(8 + -1bx)' equal to zero and attempt to solve:

Simplifying
8 + -1bx = 0

Solving
8 + -1bx = 0

Move all terms containing b to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + -1bx = 0 + -8

Combine like terms: 8 + -8 = 0
0 + -1bx = 0 + -8
-1bx = 0 + -8

Combine like terms: 0 + -8 = -8
-1bx = -8

Divide each side by '-1x'.
b = 8x-1

Simplifying
b = 8x-1
Solution
b = {x-1, 8x-1}